(x-5)^2=(x+3)(x-2)

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Solution for (x-5)^2=(x+3)(x-2) equation: 



(x-5)^2=(x+3)(x-2)

We move all terms to the left:

(x-5)^2-((x+3)(x-2))=0

We multiply parentheses ..

-((+x^2-2x+3x-6))+(x-5)^2=0



We calculate terms in parentheses: -((+x^2-2x+3x-6)), so:

(+x^2-2x+3x-6)

We get rid of parentheses

x^2-2x+3x-6

We add all the numbers together, and all the variables

x^2+x-6

Back to the equation:

-(x^2+x-6)



We get rid of parentheses

-x^2-x+(x-5)^2+6=0

We add all the numbers together, and all the variables

-1x^2-1x+(x-5)^2+6=0

We move all terms containing x to the left, all other terms to the right

-1x^2-1x+(x-5)^2=-6

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